IOCL Non Executive Recruitment 2025 Notification Released for 394 Posts, Apply Online

IOCL Non Executive Recruitment 2025: Indian Oil Corporation Limited (IOCL) has issued the latest notification for the recruitment of Non-Executive Personnel posts. A total of 394 vacancies have been announced under IOCL Non-Executive Recruitment 2025. The official notification was released on 19 December 2025, and the online application process will be open from 20 December 2025 to 09 January 2026.

• Download Notification PDF

IOCL Non Executive Recruitment 2025 Overview

Recruitment Organization	Indian Oil Corporation Limited
Post Name	Non Executive
Vacancies	394
Job Location	All India
Pay Scale	Rs. 25000-105000/-
Last Date to Apply	09 January 2026
Mode of Application	Online
Category	IOCL Non Executive Recruitment 2025 Notification PDF
Official Website	iocl.com

IOCL Non Executive Recruitment 2025 Important Dates

• Short Notice Released: 19 December 2025
• Detailed Notification Released: 20 December 2025
• Online Application Start Date: 20 December 2025
• Last Date to Apply: 09 January 2026 (up to 11:55 PM)
• CBT Exam Date: Last week of January 2026

IOCL Non Executive Recruitment 2025 Application Fee

• General / OBC / EWS: ₹300
• SC / ST / Ex-Servicemen / Persons with Disabilities: No fee
• Payment Mode: Online only

IOCL Non Executive Recruitment 2025 Age Limit Details

• Minimum Age: 18 years
• Maximum Age: 26 years
• Age Limit as on: 31 December 2025
• Age Relaxation: Applicable as per government rules

IOCL Non Executive Recruitment 2025 Educational Qualification

Post Name	Qualification
Non-Executive Posts (Refineries Division)	Engineering Diploma or ITI in the relevant trade

IOCL Non Executive Recruitment 2025 Vacancy Details

Post Name	Vacancies
Non-Executive Posts (Refineries Division)	394

Post Code	Post Name	Total Post
201	Junior Engineering Assistant-IV (Production)	232
202	Junior Engineering Assistant-IV (P&U)	37
203	Junior Engineering Assistant-IV (P&U-O&M)	22
204	Junior Engineering Assistant-IV (Electrical)	12
205	Junior Engineering Assistant-IV (Mechanical)	14
206	Junior Engineering Assistant-IV (Instrumentation)	06
207	Junior Quality Control Analyst-IV	20
208	Junior Engineering Assistant-IV (Fire & Safety)	51

IOCL Non Executive Recruitment 2025 Selection Process

The selection will be done in the following stages:

• Computer Based Test (CBT)
• Skill Test / Physical Test
• Document Verification
• Medical Examination

How to Apply for IOCL Non Executive Recruitment 2025

Candidates can apply for IOCL Non-Executive Recruitment 2025 by following the steps given below:

• Check Eligibility: Carefully read the official notification and confirm that you meet the required qualification.
• Apply Online: Click on the “Apply Online” link provided.
• Fill Application Form: Enter all the required details correctly in the online application form.
• Upload Documents: Upload the necessary documents in the prescribed format.
• Pay Application Fee: Complete the payment of the application fee through online mode, if applicable.
• Print Application: After successful submission, download and print the application form for future reference.

IOCL Non Executive Recruitment 2025 Notification PDF & Apply Online Form Link

Short Notification PDF	Click Here
Notification PDF	Click Here
Apply Online	Click Here

FAQs for IOCL Non Executive Recruitment 2025

• How many vacancies are available under IOCL Non Executive Recruitment 2025?
• A total of 394 vacancies have been announced for various posts including Junior Engineering Assistant, Junior Technical Assistant, and Junior Quality Control Analyst.
• What is the salary offered for these posts?
• The pay scale ranges from ₹25,000 to ₹1,05,000 per month, depending on the post.
• What educational qualifications are required?
• Most posts require a 3-year Diploma in the relevant engineering discipline, while the Junior Quality Control Analyst post requires a B.Sc. in PCM or Industrial Chemistry.
• What is the last date to apply online?
• The online application process will close on 09 January 2026 at 11:55 PM.